10.5. Rotational Motion Problem Set http://www.ck12.org
- a. 250 rad b. 40 rad c. 25 rad/s d. Force applied perpendicular to radius allowsαe. 0.27 kg m^2 , f.K^5 =84 J
andK^10 =340 J
5.. - Moment of inertia at the end 1/3 ML^2 at the center 1/12 ML^2 , angular momentum,L=Iωand torque,τ=Iα
change the in the same way
7.. - Lower
- Iron ball
- a. 200 N team b. 40 N c. 0.02 rad/s^2 d. 25 s
- a. Coin with the hole b. Coin with the hole
- a. weight b. 19.6 N c. plank’s length( 0 .8m)left of the pivot d. 15.7 N m, e. Ba. weight, Bb. 14.7 N, Bc.
plank’s length( 0 .3m)left of the pivot, Bd. 4.4 N m, Ca. weight, Cb. 13.6 N, Cc. plank’s length( 1 .00 m)
right of the pivot, Cd. 13.6 N m, f) 6.5 N m CC, g) no, net torque doesn’t equal zero - a. 7. 27 × 10 −^6 Hz b. 7.27 Hz
- a. 100 Hz b. 1. 25 × 105 J c. 2500 J−s d. 12,500 m−N
- 28 rev/sec
- 2300 N
- b. 771 N,1030 N c. 554 kgm^2 d. 4.81rad/sec^2
- a. 300 N b. 240N,−22 N c.. 092
- a. 2280 N b. 856 n toward beam, 106 N down c. 425 kgm^2 d. 3.39 rad/sec^2
- a.− 1 .28 Nm 20. CCW
- a. 1411 kg c. 17410 N d. angular acc goes down as arm moves to vertical