21.3. Examples http://www.ck12.org
c) First, we know that it is operating at 50% of ideal efficiency. We also know that the max efficiency of this engine
is 54%. So the engine is actually operating at
. 5 ×54%=27%
of 100% efficiency. So 240kW is 27% of what?
. 27 x=240kW⇒x=
240kW. 27
=890kW