http://www.ck12.org Chapter 16. Light
Example 1
In the situation illustrated below, the object is set up .5 m away from a converging mirror. If the focal length of the
lens is .2 m, determine (a) the location of the real image, and (b) the magnification of the image.
Solution
(a): In order to determine the location of the image, we’ll use the lens maker’s equation.
1
f
=
1
do
+
1
di
1
di
=
1
f
−
1
do
1
di
=
1
.2 m
−
1
.5 m
di=.33 m
(b): Now that we have the location of the image, we can find the magnification.
M=
−di
do
M=
−.33 m
.5 m
M=−
2
3
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