Peoples Physics Concepts

(Marvins-Underground-K-12) #1

http://www.ck12.org Chapter 3. Two-Dimensional and Projectile Motion


3.2 Velocity



  • Analyze and solve problems in two dimensions containing velocity vectors but no acceleration.


Students will learn how analyze and solve problems in two dimensions containing velocity vectors but no accelera-
tion.


Key Equations


vx=vcosθ, whereθis the angle between the velocity vector and the horizontal.


vy=vsinθ, whereθis the angle between the velocity vector and the horizontal.


∆x=vxt


∆y=vyt


Guidance

The only equation you need is that displacement in a certain direction equals the component of velocity in that
direction multiplied by the time it takes. You’ll use this once for the x-direction and once for the y-direction and
solve for what is asked.

Example 1


Question: If a river is flowing north at 2 m/s and you swim straight across (i.e. east) at 1.5 m/s, how far up shore will
you be from your starting point once you reach the other side? The river is 9 m wide.


Answer: First solve for the time it takes you to reach the other side. Let’s let north be the y-direction and the direction
across the river be the x-direction.


∆x=vxt


9 m= 1. 5 m/s×t


thus,t= 6 s


Now, use the time you are in the water to find how far the river has carried you north.


∆y=vyt


∆y= 2 m/s× 6 s


∆y= 12 m


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