CK-12 Geometry - Second Edition

(Marvins-Underground-K-12) #1

9.4. Inscribed Angles http://www.ck12.org



  1. Using your protractor measure the six angles and determine if there is a relationship between the central angle,
    the inscribed angle, and the intercepted arc.


m^6 LAM= m^6 NBP= m^6 QCR=
mLM̂= mNP̂= mQR̂=
m^6 LKM= m^6 NOP= m^6 QSR=

Inscribed Angle Theorem:The measure of an inscribed angle is half the measure of its intercepted arc.


In the picture,m^6 ADC=^12 mAĈ. If we had drawn in the central angle^6 ABC, we could also say thatm^6 ADC=
1
2 m^6 ABCbecause the measure of the central angle is equal to the measure of the intercepted arc.
To prove the Inscribed Angle Theorem, you would need to split it up into three cases, like the three different angles
drawn from Investigation 9-4. We will touch on the algebraic proofs in the review exercises.


Example 1:FindmDĈandm^6 ADB.


Solution:From the Inscribed Angle Theorem,mDĈ= 2 · 45 ◦= 90 ◦.m^6 ADB=^12 · 76 ◦= 38 ◦.


Example 2:Findm^6 ADBandm^6 ACB.

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