CK-12 Geometry-Concepts

(Marvins-Underground-K-12) #1

http://www.ck12.org Chapter 1. Basics of Geometry



  1. Find the midpoint between (3, 7) and (7, 11)


Answers:



  1. The perpendicular bisector must bisectMNand be perpendicular to it. Only


←→


OQsatisfies both requirements.

←→


SR


is just a bisector.




  1. The line shown is the perpendicular bisector. So, 3x− 6 = 21 , 3 x= 27 ,x=9. And,( 4 y− 2 )◦= 90 ◦, 4 y◦=
    92 ◦,y= 23 ◦.




  2. (
    3 + 7
    2




,


7 + 11


2


)


=


(


10


2


,


18


2


)


= ( 5 , 9 )


.


Interactive Practice


MEDIA


Click image to the left for use the URL below.
URL: http://www.ck12.org/flx/render/embeddedobject/113039

Explore More



  1. Copy the figure below and label it with the following information:


(^6) A∼= (^6) C
(^6) B∼= (^6) D
AB∼=CD
AD∼=BC

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