http://www.ck12.org Chapter 9. Circles
b)
Again, we can use the Intersecting Chords Theorem. Set up an equation and solve forx.
a)
8 · 24 = ( 3 x+ 1 )· 12
192 = 36 x+ 12
180 = 36 x
5 =xb)
32 · 21 = (x− 9 )(x− 13 )
672 =x^2 − 22 x+ 117
0 =x^2 − 22 x− 555
0 = (x− 37 )(x+ 15 )
x= 37 ,− 15However,x 6 =−15 because length cannot be negative, sox=37.
Watch this video for help with the Examples above.
MEDIA
Click image to the left for use the URL below.
URL: http://www.ck12.org/flx/render/embeddedobject/52425CK-12 Foundation: Chapter9SegmentsfromChordsB