SAT Subject Test Mathematics Level 2

(Marvins-Underground-K-12) #1

Answers and Explanations


PRACTICE TEST 4


1 . E


Since   this    is  an  absolute    value   inequality, you must    solve   two related inequalities,
and . Both of these inequalities hold when

Inequality  1:  

Inequality  2:  

So  the solution    to  the inequality  is   or 

2 . C
f(a) = | 4a | − 2 a^3 . To find the possible values of a, solve the absolute value equation | 4 a | −
2 a^3 = 66. If | 4a | − 2a^3 = 66 , then 4 a − 2 a^3 = 66 and −4a − 2a^3 = 66. Plug the values of the
answer options into each of the equations until you find one that works, starting with the
middle value: −4(−3) − 2(−3)^3 = 12 + 54 = 66 . So a = −3 is one possible value.

3 . E
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