SAT Subject Test Mathematics Level 2

(Marvins-Underground-K-12) #1

6 . B


Since   the denominator has a   lower   power,  factor  that    expression  first.

y^2     −   10y +   25  =   (y −    5)(y    −   5)
Check each numerator in the answer options to determine which polynomial gives a product
of y^3 − 6y^2 + 3y + 10 when multiplied by (y − 5).

y^3     −   6y^2    +   3y +    10  =   (y  −   5)(y^2  −   y −2).

Then

7 . A


The domain  of  a   function    cannot  include numbers that    figure  into    negative    square  roots.
This means that any expression raised to a power of must be greater than 0. x must
be less than or equal to 3 when (3 − x) is raised to the power. Any number greater than 3
would mean that a negative number is being raised to that power. So
has a domain of x ≤ 3.

8 . C
The solution to the quadratic equation ax^2 + bx + c = 0 is


Here,   a   =   1,  b   =   −8, and c   =    13.
Free download pdf