New York City SHSAT 2017

(Marvins-Underground-K-12) #1
The product of three integers must be an integer, so eliminate (A) and (D). A number that has at least one even factor is even,
so the product of two odd integers and one even integer must be even. The only even choice is 6, (C).

G
This question is simply asking for the sum of 9,899,399 and 2,082, which is 9,901,481, or choice (G).

24.


C


If the middle of five consecutive integers is 13, the first two are 11 and 12 and the last two are 14 and 15. So the sum is 11 +
12 + 13 + 14 + 15 = 65. You could have come up with this answer even more quickly if you knew that the middle term in a
group of consecutive numbers is equal to the average of the group of numbers. In other words, the average of these five
integers is 13, so their sum would be 5 • 13 = 65.

25.


F


Remember, to divide powers with the same base, you need to subtract the exponents.

26.


C


Remember, a negative number raised to an odd power is negative.

− 2^3 (1 − 2)^3 + (− 2)^3 = −8 (−1)^3 + −8 = 8 − 8 = 0

27.


H


The mean (or average) is the sum of the terms divided by the number of terms. The numbers included are 11, 13, 15, and 17.
Note that 19 is not in the set, since n is less than 19. The mean is an even number although the numbers in the set are all odd.

28.


D


Stay calm and simply substitute the number on the left for a and the number on the right for b in the formula given for the
strange symbol. First convert b to an improper fraction: So the numerator is 3 times or (simplifying the fraction) 3
times Dividing by is the same as multiplying by. So we have

29.


J


Pay per week is the same as pay per day times the number of days in the week. This is also the same as pay per hour times the
number of hours worked in a day times the number of days in the week. This becomes

30.

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