I
V»
c
C
5
u
to
V)
4.
- No, they are not the same. Your speed on the ski lift
is constant. Your speed going downhill is not.
b.
Ti m e
- The three runners start at the same time. At time A,
one runner has a fast start, and the other two are a little
slower. At B, the second-place runner catches up to the
first-place runner and passes the first-place runner in
order to win at time C. At C, the runner that was in third
place catches up to the original first-place runner to
finish second. At D, only the original first-place runner
remains in the race. 21. B 23.9.35 3.50££ = 0.10,
or a 10% increase. Another 10% increase would
bring your hourly wage to 1.1(9.35) = 10.285, or
$10.29. One further 10% increase would bring
your rate to 1.1(10.29) = 11.3135, or $11.32. - {-3 , -1 , 1, 3,4, 5, 7, 9} 25.(1}
- {-1, 1,3,4, 5,7,9, 12} 27. {1,4}
- Co n n i e' s
Age
Donald's
Age
[ 0 4 ]
[ 1 5 J
(^2) 6 J
[ 3 7 ]
v J
d
/
Y-
/
/
c
0 1 2 3 4 5
Tim e
(hours)
Number
of Cards
00
1 3
26
39
0 1 2 3
C=3 h
Lesson 4-2
Go t It? l a.
pp. 240-245
f \
Number of Triangles 123 4
Per i m et er 10 14 18 22
Multiply the number of
triangles by 4 and add 6;
y = 4x+ 6.
b. Add 4. c. The 4x part of the equation means that for
each triangle the perimeter is increased by 4. If you know
the perimeter of n triangles, then the perimeter when 1
more triangle is added will increase by 4.
2a. Yes; the value of y is 8 more
than twice the value of x;
y = 2x + 8.
b. No; the input value 1 has
more than one output value.
16
12
8f
4
0,
Lesso n Ch eck
1a.
Of0 1 2 3 4
10
8f
6
4
2
0, 2 3
0 1 2 3
y increases by 1 for each
increase of 1 forx.
For each increase of 1 in x,
y decreases by 2.
c. x is 3 for any value of y
c
Number of
Sq u a r e s^12341030 n
Per i m et er 4 68102262 In + 2
- independent: number of times you brush your teeth;
dependent: amount of toothpaste 4. a and b are
functions because for each input there is a unique
output, but c is not a function because there is more than
one output value for the input value 3. 5. No; the
graph is not a line.
Ex e r c i se s
f' >
Number of
Pen t ag o n s^123
Per i m et er 5 8 11
J
Multiply the number of pentagons
by 3 and add 2; y = 3x + 2. B 10 12
| 8
I 6
St 4
2
0,
0 1 2 3 4
0 1 2 3
Number of
Pen t ag o n s
876