Beginning Algebra, 11th Edition

(Marvins-Underground-K-12) #1
Applying the Multiplication Property of Equality

Solve


Multiply each side by , the reciprocal of.

Multiplicative inverse property

Check to confirm that the solution set is 586. NOW TRY


w= 8


1 #w=


4


3


#^6


1


3
4

4

3


4


3



3


4


w=


4


3


6


3


4


w= 6


3

4 w=6.


EXAMPLE 5

SECTION 2.2 The Multiplication Property of Equality 95


NOW TRY
EXERCISE 5
Solve.^47 z=- 16


NOW TRY
EXERCISE 6
Solve .-x= 9


NOW TRY
EXERCISE 7
Solve. 9 n- 6 n= 21


Multiplicative identity property;
multiply fractions.

In Section 2.1,we obtained in our alternative solution to Example 4.


We reasoned that since the additive inverse (or opposite) of xis , then xmust


equal 17. We can use the multiplication property of equality to obtain the same result.


- 17


- x=- 17


Applying the Multiplication Property of Equality

Solve


Multiply each side by.
Associative property; multiply.
Multiplicative inverse property
Multiplicative identity property

CHECK Original equation


Let

✓ True


The solution, 17, checks, so 5176 is the solution set. NOW TRY


- 17 =- 17


- 1172 - 17 x=17.


- x=- 17


x= 17


1 x= 17


3 - 11 - 124 x= 17


- 11 - 1 x 2 = - 11 - 172 - 1


- 1 x=- 17 - x=- 1 x


- x=- 17


- x=-17.


EXAMPLE 6

These steps are
usually omitted.

OBJECTIVE 2 Simplify, and then use the multiplication property of equality.


Combining Like Terms When Solving

Solve


Combine like terms.

Divide by 11.

Multiplicative identity property; divide.

CHECK Original equation


Let.
Multiply.

✓ True


Since a true statement results, the solution set is 536. NOW TRY


33 = 33


15 + 18  33


5 132 + 6 132  33 m= 3


5 m+ 6 m= 33


m= 3


11 m


11


=


33


11


11 m= 33


5 m+ 6 m= 33


5 m+ 6 m= 33.


EXAMPLE 7

NOW TRY ANSWERS



  1. 5 - 286 6. 5 - 96 7. 576

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