OBJECTIVE 1 Graph linear inequalities in two variables.Consider the
graph in FIGURE 35. The graph of the line divides the points in the rectan-
gular coordinate system into three sets:
1.Those points that lie on the line itself and satisfy the equation like
and
2.Those that lie in the region above the line and satisfy the inequality
like and
3.Those that lie in the region below the line and satisfy the inequality
like and ,.
The graph of the line is called the boundary linefor the inequalities
and
Graphs of linear inequalities in two variables are regions in the real number plane
that may or may not include boundary lines.
Graphing a Linear Inequality
Graph
The inequality means that
We begin by graphing the equation a line with intercepts and
as shown in FIGURE 36. This boundary line divides the plane into two regions,
one of which satisfies the inequality. A test pointgives a quick way to find the cor-
rect region. We choose any point noton the boundary line and substitute it into the
given inequality to see whether the resulting statement is true or false. The point
is a convenient choice.
Original inequality
Let and
True
Since the last statement is true, we shade the region that includes the test point
See FIGURE 36. The shaded region, along with the boundary line, is the
desired graph.
1 0, 0 2.
0 ... 6
0 + 0 ...
?
6
2102 + 3102 ... x= 0 y=0.
?
6
2 x+ 3 y... 6
1 0, 0 2
1 3, 0 2 ,
2 x+ 3 y= 6, 1 0, 2 2
2 x+ 3 y 66 or 2 x+ 3 y= 6.
2 x+ 3 y... 6
2 x+ 3 y...6.
EXAMPLE 1
x+y 75 x+ y 6 5.
x+ y= 5
3 1 0, 0 2 1 - 3 - 124
x+y 65
3 1 5, 3 2 1 2, 4 24
x+y 75
1 0, 5 2 , 1 2, 3 2 , 1 5, 0 24
xy 53
x+ y= 5
224 CHAPTER 3 Linear Equations and Inequalities in Two Variables; Functions
NOW TRY
EXERCISE 1
Graph x+ 3 y...6.
x
y
x + y = 5 (2, 4)
(0, 0)
(–3, –1)
(5, 3)
x + y > 5
x + y < 5
FIGURE 35
Use as
a test point.
1 0, 0 2
(0, 2)
(3, 0)
yy
x
2 x 3 y 6
Boundary
line
Test
point
2 x 3 y 6
(0, 0)
FIGURE 36 NOW TRY
NOW TRY ANSWER
x
y
0
x + 3y Ä 6
2
6
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