Beginning Algebra, 11th Edition

(Marvins-Underground-K-12) #1

248 CHAPTER 4 Systems of Linear Equations and Inequalities


OBJECTIVES A system of linear equations,often called a linear system,consists of two or more


linear equations with the same variables.


Linear systems

3 x- y=- 5 - y= 4 - 2 x y= 3


2 x+ 3 y= 4 x+ 3 y= 1 x- y= 1


Solving Systems of Linear Equations by Graphing


4.1


1 Decide whether a
given ordered pair
is a solution of a
system.
2 Solve linear systems
by graphing.
3 Solve special
systems by
graphing.
4 Identify special
systems without
graphing.

NOTE In the system on the right, think of as an equation in two variables by


writing it as 0 x+ y=3.


y= 3


OBJECTIVE 1 Decide whether a given ordered pair is a solution of a


system. A solution of a systemof linear equations is an ordered pair that makes


both equations true at the same time. A solution of an equation is said to satisfythe


equation.


Determining Whether an Ordered Pair Is a Solution

Decide whether the ordered pair is a solution of each system.


(a)


To decide whether is a solution of the system, substitute 4 for xand


for yin each equation.


Substitute. Substitute.
Multiply. Multiply.

✓ True ✓ True


Because satisfies both equations, it is a solution of the system.


(b)


Again, substitute 4 for xand for yin both equations.


Substitute. Substitute.
Multiply. Multiply.

✓ True False


The ordered pair is not a solution of this system because it does not satisfy


the second equation. NOW TRY


OBJECTIVE 2 Solve linear systems by graphing. The set of all ordered


pairs that are solutions of a system is its solution set.One way to find the solution


set of a system of two linear equations is to graph both equations on the same axes.


1 4, - 32


- 7 =- 7 0 = 2


8 + 1 - 152 - 7 12 + 1 - 122  2


2142 + 51 - 32 - 7 3142 + 41 - 32  2


2 x+ 5 y=- 7 3 x+ 4 y= 2


- 3


3 x+ 4 y= 2


2 x+ 5 y=- 7


1 4, - 32


- 8 =- 8 6 = 6


4 + 1 - 122 - 8 12 + 1 - 62  6


4 + 41 - 32 - 8 3142 + 21 - 32  6


x+ 4 y=- 8 3 x+ 2 y= 6


1 4, - 32 - 3


3 x+ 2 y= 6


x+ 4 y=- 8


1 4, - 32


NOW TRY EXAMPLE 1

EXERCISE 1
Decide whether the ordered
pair is a solution of
each system.


(a)


(b)


2 x+y= 12

3 x-y= 13

x- y= 7

2 x+ 5 y= 20

1 5, 2 2

NOW TRY ANSWERS



  1. (a)no (b)yes


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