- ; 15. ;
3 x + 2y = 8
y
0 x
4
8
3
y = 2x + 5
5
0
-^52
x
y
A- 25 , 0B 1 0, 5 2 A 38 , 0B 1 0, 4 2
Answers to Selected Exercises A-9
56.no x-intercept; ; 0 57. 58.
63.Since the graph rises from left to right, the slope is positive.
- 66.2003: 41.7; 2004: 42.2; 2005: 42.7; 2006: 43.2
Chapter 3 Test (pages 244–245)
[3.1]1. 2.no [3.2]3.To find the x-intercept, let
and to find the y-intercept, let x=0.
- 6, -10, - 5 y=0,
1 2002, 41.2 2 , 1 2007, 43.7 2 y=0.5x-959.8
y < –4x
0
y
x
x – 2y ≤ 6
0
y
x
y=- 47 x-^237 y=- 5
y – 5 = 0
0
y
x
1 0, 5 2 y=- 41 x- 45 y=- 3 x+ 30
- ; ;
y = –2x – 5
0
y
x
–5
5
- 2
A- 25 , 0B 1 0, - 52 - 2 55. ; ;
x + 3y = 0
0
1
y
–3 x
1 0, 0 21 0, 0 2 - (^13)
- 18.undefined 19. 3 20. 0 21. 22. 23.
- (a) 2 (b) 25.parallel 26.perpendicular 27.neither
- ;
It is not possible to express this equation in the form
- ;
39.not a function; domain: ; range:
40.function; domain: ; range:
41.not a function 42.function 43.function 44.function
- (a) 8 (b) 46. (a) 7 (b) 1 47. (a) 5 (b) 2 48.A
49.C, D 50.A, B, D 51.D 52.C 53.B- 1
5 8, 7, 6, 5, 4 6 5 3, 4, 5, 6, 7 6
5 - 2, 0, 2 6 5 4, 8, 5, 3 6
x
y
0
x – 2y ≥ 0
x
y
0
2 x – 3y > –6
x
y
0
3 x + 5y > 9
y=mx+b.
y=-^34 x- 41 y=- 14 x+ 23 y= 1 x= 31
y=-x+^23 y=- 12 x+ 4 y=x- 7 y= 32 x+^143
1
3
3
- 2
1
3
3
- (^2)
1
2
x + 2y = – 4
–4 –2^0 x
y
1 - 4, 0 2 ; 1 0, - 22
4.x-intercept: ;
y-intercept:
x
y
0
3 x + y = 6
6
2
1 0, 6 2
1 2, 0 2
[3.5]17. 18.
[3.1–3.4]19.The slope is negative, since sales are decreasing.
;
21.174 thousand; The equation gives a good approximation of the actual
sales. 22.In 2007, worldwide snowmobile sales were 160 thousand.
[3.6]23. (a)not a function (b)function; domain: ;
range: 24.not a function 25. 1
Chapters 1– 3 Cumulative Review Exercises
(page 246)
[1.1]1. 2. 6 [1.5]3. 7 [1.6]4.
[1.2–1.6]5.true 6. [1.7]7.distributive property
[1.8]8. [2.5]9. [2.3]10. 11.
[2.6]12. [2.8] 13.
[2.4]16.high school diploma: $30,732; bachelor’s degree: $50,856
[1.1, 2.6]17. (a)$7000(b)$10,000 18.about $30,000
[3.2]19. ; [3.3]20.
[3.2]21. [3.3]22.perpendicular
[3.4]23. 24.
SYSTEMS OF LINEAR EQUATIONS
AND INEQUALITIES
Connections (page 253) 1. 2.
3.
Section 4.1 (pages 253–257)
1.A; The ordered-pair solution must be in quadrant II, and
1 - 4, - 42 is in quadrant III. 3.no 5.yes 7.yes 9.no
51 1.5, -1.5 26
51 - 1, 5 26 51 0.25, -0.5 26
4
y= 3 x- 11 y= 4
–3x + 4y = 12
3
–4 0
y
x
3
1 - 4, 0 21 0, 3 (^24)
–4 0
1 - q, - 44
00
1 0, q 2
–2.6–2.6–1–1 00
5 - 136 1 - 2.6, q 2
h= 5 - 16 526
3 V
p+ (^2) pr 2
43
73
18 , or 4
1
18
301
40 , or 7^
21
40
526
5 0, 1, 2 6
1 0, 209 2 , 1 7, 160 2 y=- 7 x+ 209
3 x – y > 0
0
y
x x
y
0
x + y ≤ 3
6.x-intercept: ;
y-intercept: none
x + 3 = 0
0
y
x
1 - 3, 0 2
8.x-intercept: ;
y-intercept:
x – y = 4
–4
0 4
y
x
1 0, - 42
1 4, 0 2 [3.3]9. 10. 11.undefined
- 0 13.
[3.4]14. 15.
16.y=- 9 x+ 12
y= 2 x+ 6 y= 25 x- 4
5
2
- 83 - 2
7.x-intercept: none;
y-intercept:
y = 1
0
y
x
1 0, 1 2
5.x-intercept: ;
y-intercept:
y – 2x = 0
2
1
y
x
1 0, 0 2
1 0, 0 2