3.3 Linear Equations in Two Variables
Slope-Intercept Form
Point-Slope Form
Standard Form
Horizontal Line
Vertical Line
xa
yb
AxByC
yy 1 m 1 xx 12
ymxb y-intercept is.
is on the line,
Standard form
Horizontal line
x=- 1 Vertical line
y= 4
2 x- 5 y= 8
y- 3 = 41 x- 52 1 5, 3 2 m=4.
y= 2 x+ 3 m=2, 1 0, 3 2
CONCEPTS EXAMPLES
CHAPTER 3 Summary 201
3.5 Introduction to Relations and
Functions
A functionis a set of ordered pairs such that, for each first
component, there is one and only one second component.
The set of first components is called the domain,and the
set of second components is called the range.
defines a function ƒ with domain, the
set of x-values, and range, the set of y-values,
y=x^2 defines a function with domain 1 - q, q 2 and range 3 0, q 2.
5 - 1, 0, 1 6 5 4, 6 6.
ƒ= 51 - 1, 4 2 , 1 0, 6 2 , 1 1, 4 26
3.4 Linear Inequalities in Two Variables
Graphing a Linear Inequality
Step 1 Draw the graph of the line that is the boundary.
Make the line solid if the inequality involves
or. Make the line dashed if the inequality
involves or
Step 2 Choose any point not on the line as a test point.
Substitute the coordinates into the inequality.
Step 3 Shade the region that includes the test point if
the test point satisfies the original inequality.
Otherwise, shade the region on the other side of
the boundary line.
6 7.
Ú
...
Graph
Draw the graph of Use a solid line because of the
inclusion of equality in the symbol
Choose , for example.
True
Shade the side of the line that includes
1 0, 0 2.
0 ... 6
2102 - 3102 ...
?
6
10 , 02
....
2 x- 3 y=6.
2 x- 3 y...6.
y
(0, 0) 0 3 x
2
3.6 Function Notation and Linear
Functions
To evaluate a function ƒ, where defines the range
value for a given value of xin the domain, substitute the
value wherever xappears.
To write an equation that defines a function ƒ in function
notation, follow these steps.
Step 1 Solve the equation for y.
Step 2 Replace ywith ƒ 1 x 2.
ƒ 1 x 2 If then
Write using notation for a function ƒ.
Subtract 2x.
Divide by 3.
ƒ 1 x 2 =- y=ƒ 1 x 2
2
3
x+ 4
y=-
2
3
x+ 4
3 y=- 2 x+ 12
2 x+ 3 y= 12
ƒ 112 = 12 - 7112 + 12 =6.
ƒ 1 x 2 =x^2 - 7 x+12,