Intermediate Algebra (11th edition)

(Marvins-Underground-K-12) #1

NOTEThe factored form in Example 8can be written in other ways, such as


and


Verify that these both give the original trinomial when multiplied.


Factoring a Trinomial with a Common Factor

Factor


GCF 8 y

= 8 y 12 y- 121 y+ 22 Factor the trinomial.


= 8 y 12 y^2 + 3 y- 22 =


16 y^3 + 24 y^2 - 16 y


16 y^3 + 24 y^2 - 16 y.


EXAMPLE 9


1 - 3 x- 221 x- 62 13 x+ 221 - x+ 62.


SECTION 6.2 Factoring Trinomials 331


NOW TRY

OBJECTIVE 4 Factor by substitution.


Factoring a Polynomial by Substitution

Factor


Since the binomial appears to powers 2 and 1, we let a substitution variable


represent We may choose any letter we wish except x. We choose t.


Let
Factor.
Replace twith
Simplify.

= 12 x+ 321 x+ 72 NOW TRY


= 12 x+ 6 - 321 x+ 72


= 321 x+ 32 - 3431 x+ 32 + 44 x+3.


= 12 t- 321 t+ 42


= 2 t^2 + 5 t- 12 t=x+3.


21 x+ 322 + 51 x+ 32 - 12


x+3.


x+ 3


21 x+ 322 + 51 x+ 32 - 12.


EXAMPLE 10


CAUTION Remember to make the final substitution of for t in


Example 10.


x+ 3


NOW TRY
EXERCISE 9
Factor 12y^3 + 33 y^2 - 9 y.


NOW TRY ANSWERS



  1. 3 y 14 y- 121 y+ 32


NOW TRY
EXERCISE 10
Factor.


31 a+ 222 - 111 a+ 22 - 4


  1. 13 a+ 721 a- 22


Factoring a Trinomial in Form

Factor


The variable yappears to powers in which the greater exponent is twice the lesser


exponent. We can let a substitution variable represent the variable to the lesser power.


Here, we let


Substitute tfor.
Factor.

= 13 y^2 - 4212 y^2 + 52 t=y 2


= 13 t- 4212 t+ 52


= 6 t^2 + 7 t- 20 y^2


= 61 y^222 + 7 y^2 - 20 y^4 = 1 y^222


6 y^4 + 7 y^2 - 20


t=y^2.


6 y^4 + 7 y^2 - 20.


EXAMPLE 11 ax (^4) +bx (^2) +c
Don’t stop here.
Replace twith y^2.
NOW TRY


NOTE Some students feel comfortable factoring polynomials like the one in


Example 11directly, without using the substitution method.


NOW TRY
EXERCISE 11
Factor 6x^4 + 11 x^2 +3.



  1. 13 x^2 + 1212 x^2 + 32


Remember the
common factor.
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