Intermediate Algebra (11th edition)

(Marvins-Underground-K-12) #1

CHECK


Let

Simplify;

✓ True


Check that 1 is a solution. The solution set is E-^72 , 1F. NOW TRY


15 = 15


1 - 6 2a-


5


2


b  9 + 6


1 - 7 + 1 2a- 1 = 22.


5


2


b  2 a


9


2


b + 6


c 2 a- x=- 27.


7


2


b + 1 da-


7


2


+ 1 b  2 c 1 - a-


7


2


bd+ 6


12 x+ 121 x+ 12 = 211 - x 2 + 6


SECTION 6.5 Solving Equations by Factoring 347


NOW TRY
EXERCISE 5
Solve.


= 41 x+ 42 - 4

1 x+ 3212 x- 12

NOW TRY ANSWERS



  1. E-3, 25 F 6.E-4, 0, 23 F


The zero-factor property can be extended to solve certain polynomial equations


of degree 3 or greater, as shown in the next example.


Solving an Equation of Degree 3

Solve


Add 6xto each side.
Multiply each side by
Factor out x.
Factor the trinomial.

or or


x= 3 or x=- 2


x= 0 x- 3 = 0 x + 2 = 0


x 1 x- 321 x+ 22 = 0


x 1 x^2 - x- 62 = 0


x^3 - x^2 - 6 x= 0 - 1.


- x^3 + x^2 + 6 x= 0


- x^3 + x^2 =- 6 x


- x^3 +x^2 =- 6 x.


NOW TRY EXAMPLE 6


EXERCISE 6
Solve 12x= 2 x^3 + 5 x^2.


Extend the zero-factor property
to the three variablefactors.
Remember to set
xequal to 0.

Check that the solution set is 5 - 2, 0, 3 6. NOW TRY


OBJECTIVE 2 Solve applied problems that require the zero-factor property.


An application may lead to a quadratic equation.


Using a Quadratic Equation in an Application

A piece of sheet metal is in the shape of a parallelogram. The longer sides of the par-


allelogram are each 8 m longer than the distance between them. The area of the piece


is Find the length of the longer sides and the distance between them.


Step 1 Readthe problem again. There will be two answers.


Step 2 Assign a variable.


Let the distance between the longer sides


and x+ 8 =the length of each longer side. (See FIGURE 1.)


x=


48 m^2.


EXAMPLE 7


x + 8

x + 8

x

FIGURE 1
Free download pdf