Intermediate Algebra (11th edition)

(Marvins-Underground-K-12) #1

(b)


Factor.

Fundamental property

(c)


Write as

Factor.

Fundamental property

(d)


Factor.

Multiply; lowest terms

(e)


Factor.

= Lowest terms NOW TRY


1


x+ 4


=


x- 6


1 x- 622



1 x+ 321 x- 62


1 x+ 321 x+ 42


x- 6


x^2 - 12 x+ 36


#x


(^2) - 3 x- 18


x^2 + 7 x+ 12


=


1 x+ 221 x- 12


x 1 x+ 12


=


x 1 x+ 22


x+ 1



1 x+ 121 x- 12


x^21 x+ 12


x^2 + 2 x


x+ 1


x


(^2) - 1


x^3 + x^2


=


3


5


=


p- 4


1


#^3


51 p- 42


p 4

= p 4 1.


p- 4


1


#^3


5 p- 20


1 p- 42 #


3


5 p- 20


=


k


k- 4


k 1 k- 12


1 k+ 521 k- 42


=


1 k+ 521 k- 32


1 k- 321 k- 12



k^2 + 2 k- 15


k^2 - 4 k+ 3


k


(^2) - k


k^2 + k- 20


SECTION 7.1 Rational Expressions and Functions; Multiplying and Dividing 367


Remember to include
1 in the numerator
when all other factors
are eliminated.

NOW TRY
EXERCISE 4
Multiply.


(a)


(b)


m^2 + 2 m- 15
m^2 - 5 m+ 6

m


(^2) - 4
m^2 + 5 m
8 t^2
t^2 - 4
#^3 t+^6
9 t
NOW TRY ANSWERS



  1. (a) 31 t^8 - t 22 (b)mm+^2


OBJECTIVE 5 Find reciprocals of rational expressions.The rational numbers


and are reciprocals of each other if they have a product of 1. The reciprocalof a


rational expression is defined in the same way: Two rational expressions are recip-


rocals of each other if they have a product of 1. Recall that 0 has no reciprocal.


The table shows several rational expressions and their reciprocals.


c
d

a
b

OBJECTIVE 6 Divide rational expressions.


Reciprocals have a product
of 1.

Rational
Expression Reciprocal

3, or

undefined
0
4

2
m^2 - 9 m

m^2 - 9 m
2

k
5

5
k

1
3

3
1

Finding the Reciprocal
To find the reciprocal of a nonzero rational expression, interchange the nu-
merator and denominator of the expression.

Dividing Rational Expressions
To divide two rational expressions, multiplythe first (the dividend) by the
reciprocal of the second (the divisor).
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