Intermediate Algebra (11th edition)

(Marvins-Underground-K-12) #1

NOTE We could have used factoring to solve the equation in Example 1.


Factor.

or Zero-factor property


or Solve each equation.


or Same solutions as in Example 1


When solving quadratic equations, it is a good idea to try factoring first. If the poly-


nomial cannot be factored or if factoring is difficult, then use the quadratic formula.


Using the Quadratic Formula (Irrational Solutions)

Solve


Write the equation in standard form as


Quadratic formula

Simplify.

Factor.

Lowest terms

The solution set is e. NOW TRY


2  23
2

f

x=


2  23


2


x=


4 A 2  23 B


4122


x = 248 = 216 # 23 = 423


8  423


8


x=


8  248


8


x=


8  264 - 16


8


x = a=4, b=-8, c= 1


- 1 - 82  21 - 822 - 4142112


2142


x=


- b 2 b^2 - 4 ac


2 a


4 x^2 - 8 x+ 1 =0.


4 x^2 = 8 x- 1.


EXAMPLE 2


x=-


1


2


x=


4


3


3 x= 4 2 x=- 1


3 x- 4 = 0 2 x+ 1 = 0


13 x- 4212 x+ 12 = 0


6 x^2 - 5 x- 4 = 0


SECTION 9.2 The Quadratic Formula 507


Factor first. Then
divide out the
common factor.

CAUTION


1. Every quadratic equation must be expressed in standard form


before we begin to solve it,whether we use factoring or


the quadratic formula.


2. When writing solutions in lowest terms, be sure to FACTOR FIRST. Then


divide out the common factor,as shown in the last two steps in Example 2.


ax^2 bxc 0


NOW TRY
EXERCISE 2
Solve. 3 x^2 + 1 =- 5 x


NOW TRY ANSWER



  1. e

    • 5  213
      6
      f




This is a
key step.
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