8 ROTATIONAL MOTION 8.7 Torque
Figure 79: A rotating bicycle wheel.
the tangential motion of the wheel, yields
M ̇v = f sin θ, (8.52)
where M is the mass of the wheel (which is assumed to be concentrated in the
wheel’s rim).
Let us now convert the above expression into a rotational equation of motion.
If ω is the instantaneous angular velocity of the wheel, then the relation between
ω and v is simply
v = b ω. (8.53)
Since the wheel is basically a ring of radius b, rotating about a perpendicular
symmetric axis, its moment of inertia is
I = M b^2. (8.54)
Combining the previous three equations, we obtain
where
I ω ̇ = τ, (8.55)
τ = f b sin θ. (8.56)
Equation (8.55) is the angular equation of motion of the wheel. It relates the
wheel’s angular velocity, ω, and moment of inertia, I, to a quantity, τ, which is
known as the torque. Clearly, if I is analogous to mass, and ω is analogous to
f sin f
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b