McGraw-Hill Education GRE 2019

A

B

C

Point A is the center of the larger circle above. Point

B is the center of the smaller circle above.

QUANTITY A QUANTITY B

7. A B C D

Exercise Answers

Discrete Quantitative Questions

1. B Use the area formula:
   49π = π(r^2 )
   49 = r^2
   r = 7
   The diameter is thus 14. The circumference = 14π


2. A Use the circumference formula:
   πd = π
   d = 1
   r =^12
   Now substitute^12 for r in the area formula: area = π(^12 )^2 = π 4.


3. C If the area of the square is 16, then each of its sides = √ 16 = 4. The side of
   the square represents the diameter of the circle, so the circle’s diameter is
   also 4. Thus the radius of the circle is 2. Substitute 2 for the radius in the area
   formula: area = π(r^2 ) = π(2^2 ) = 4π.

The ratio of the area of

the smaller circle to the

area of the larger circle

1

2

418 PART 4 ■ MATH REVIEW

04-GRE-Test-2018_313-462.indd 418 12/05/17 12:05 pm