212 Basic Engineering Mathematics
(a) Applying the sine rule,
AB
sin50◦
=
AO
sinB
from which sinB=
AOsin50◦
AB
=
10 .0sin50◦
30. 0
= 0. 2553
Hence,B=sin−^10. 2553 = 14. 79 ◦(or 165. 21 ◦,
which is not possible)
Hence,the connecting rodABmakes an angle
of 14.79◦with the horizontal.
AngleOAB= 180 ◦− 50 ◦− 14. 79 ◦= 115. 21 ◦
Applying the sine rule:
30. 0
sin50◦
=
OB
sin115. 21 ◦
from which OB=
30 .0sin115. 21 ◦
sin50◦
= 35 .43cm
(b) Figure 23.18 shows the initial and final positions
of the crank mechanism.
508
O
30.0 cm 1208
BB 9
A A^9
10.0 cm
Figure 23.18
In triangleOA′B′, applying the sine rule,
30. 0
sin120◦
=
10. 0
sinA′B′O
from which sinA′B′O=
10 .0sin120◦
30. 0
= 0. 28868
Hence, A′B′O=sin−^10. 28868 = 16. 78 ◦ (or
163. 22 ◦, which is not possible)
AngleOA′B′= 180 ◦− 120 ◦− 16. 78 ◦= 43. 22 ◦
Applying the sine rule,
30. 0
sin120◦
=
OB′
sin43. 22 ◦
from whichOB′=
30 .0sin43. 22 ◦
sin120◦
= 23 .72cm
Since OB= 35 .43cm and OB′= 23 .72cm,
BB′= 35. 43 − 23. 72 = 11 .71cm
Hence,B moves 11.71cm when angle AOB
changes from 50◦to 120◦.
Problem 13. The area of a field is in the form of a
quadrilateralABCDas shown in Figure 23.19.
Determine its area
62.3m
21.4m
39.8m
1148
568
B
D
C
A
42.5m
Figure 23.19
A diagonal drawn fromBtoDdivides the quadrilateral
into two triangles.
Area of quadrilateralABCD
=area of triangleABD
+area of triangleBCD
=
1
2
( 39. 8 )( 21. 4 )sin114◦
+
1
2
( 42. 5 )( 62. 3 )sin 56◦
= 389. 04 + 1097. 5
=1487m^2
Now try the following Practice Exercise
PracticeExercise 93 More practical
situations involving trigonometry (answers
on page 350)
- Three forces acting on a fixed point are repre-
sented by the sides of a triangle of dimensions
7 .2cm, 9 .6cm and 11.0cm. Determine the
angles between thelines of action and thethree
forces. - A vertical aerialAB,9.60m high, stands on
groundwhich is inclined12◦to the horizontal.
AstayconnectsthetopoftheaerialAtoapoint
Con the ground 10.0m downhill fromB,the
foot of the aerial. Determine (a) the length of
the stay and (b) the angle the stay makes with
the ground. - A reciprocating engine mechanism is shown
in Figure 23.20. The crankABis 12.0cm long
and the connecting rodBCis 32.0cm long.
For the position shown determine the length
ofACand the angle between the crank and the
connecting rod.