Introduction to differentiation 315
chordJK.BymovingJnearer and nearer to
K, determine the gradient of the tangent of the
curve atK.
34.4 Differentiation from first principles
In Figure 34.4, Aand Bare two points very close
together on a curve,δx(deltax)andδy(deltay)rep-
resenting small increments in thexandydirections,
respectively.
0
y
f(x)
f(x 1
x)
y
x
x
A(x, y)
B(x 1
x, y 1
y)
Figure 34.4
Gradient of chord AB=
δy
δx
however, δy=f(x+δx)−f(x)
Hence,
δy
δx
=
f(x+δx)−f(x)
δx
Asδxapproaches zero,
δy
δx
approaches a limiting value
and the gradient of the chord approaches the gradient of
the tangent atA.
When determining the gradient of a tangent to a curve
thereare two notationsused. The gradient of the curve
atAin Figure 34.4 can either be written as
limit
δx→ 0
δy
δx
or limit
δx→ 0
{
f(x+δx)−f(x)
δx
}
InLeibniz notation,
dy
dx
=limit
δx→ 0
δy
δx
Infunctional notation,
f′(x)=limit
δx→ 0
{
f(x+δx)−f(x)
δx
}
dy
dx
is the same asf′(x)and is called thedifferential
coefficientor thederivative. The process of finding the
differential coefficient is calleddifferentiation.
Summarizing, the differential coefficient,
dy
dx
=f′(x)=limit
δx→ 0
δy
δx
=limit
δx→ 0
{
f(x+δx)−f(x)
δx
}
Problem 3. Differentiate from first principles
f(x)=x^2
To ‘differentiate from first principles’ means ‘to find
f′(x)’ using the expression
f′(x)=limit
δx→ 0
{
f(x+δx)−f(x)
δx
}
f(x)=x^2 and substituting (x+δx) for x gives
f(x+δx)=(x+δx)^2 =x^2 + 2 xδx+δx^2 , hence,
f′(x)=limit
δx→ 0
{
(x^2 + 2 xδx+δx^2 )−(x^2 )
δx
}
=limit
δx→ 0
{
2 xδx+δx^2
δx
}
=limit
δx→ 0
{ 2 x+δx}
Asδx→ 0 ,{ 2 x+δx}→{ 2 x+ 0 }.
Thus,f′(x)= 2 xi.e.the differential coefficient ofx^2
is 2x.
This means that the general equation for the gradient of
the curvef(x)=x^2 is 2x. If the gradient is required at,
say,x=3, then gradient= 2 ( 3 )= 6.
Differentiation from first principles can be a lengthy
process and we do not want to have to go through this
procedureeverytimewewant todifferentiateafunction.
In reality we do not have to because from the above
procedure has evolved a setgeneral rule,whichwe
consider in the following section.
34.5 Differentiation ofy=axnby the
general rule
From differentiation by first principles, a general rule
for differentiatingaxnemerges whereaandnare any
constants. This rule is
ify=axnthen
dy
dx
=anxn−^1
or iff(x)=axnthenf′(x)=anxn−^1