Basic Engineering Mathematics, Fifth Edition

(Amelia) #1

318 Basic Engineering Mathematics



  1. y=


1
x


  1. y= 12

  2. y=x−


1
x^2


  1. y= 3 x^5 − 2 x^4 + 5 x^3 +x^2 − 1

  2. y=


2
x^3


  1. y= 4 x( 1 −x)

  2. y=



x 12. y=


t^3


  1. y= 6 +


1
x^3


  1. y= 3 x−


1

x

+

1
x


  1. y=(x+ 1 )^2 16. y=x+ 3



x


  1. y=( 1 −x)^2 18. y=


5
x^2


1

x^7

+ 2


  1. y= 3 (t− 2 )^2 20. y=


(x+ 2 )^2
x


  1. Find the gradient of the following curves at
    the given points.
    (a) y= 3 x^2 atx= 1
    (b) y=



xatx= 9
(c) y=x^3 + 3 x−7atx= 0

(d) y=

1

x

atx= 4

(e) y=

1
x

atx= 2

(f) y=( 2 x+ 3 )(x− 1 )atx=− 2


  1. Differentiate f(x)= 6 x^2 − 3 x+5andfind
    the gradient of the curve at
    (a) x=−1(b)x= 2

  2. Find the differential coefficient of
    y= 2 x^3 + 3 x^2 − 4 x−1 and determine the
    gradient of the curve atx=2.

  3. Determine the derivative of
    y=− 2 x^3 + 4 x+7 and determine the
    gradient of the curve atx=− 1. 5


34.6 Differentiation of sine and cosine functions

Figure 34.5(a) shows a graph ofy=sinx. The gradient
is continually changing as the curve moves from 0 to

y

0
(a)

(b)
0

y 5 sinx

x radians

x radians

1

2

2

A

A 9

09

C 9

B 9

D 9

BD

C


2

d
dx
1 dydx

2 

2 

3 
2



 3 
2

(sinx) 5 cosx


2

Figure 34.5

AtoBtoCtoD. The gradient, given by
dy
dx

,maybe
plotted in a corresponding position belowy=sinx,as
shown in Figure 34.5(b).
At 0, the gradient is positiveand is at its steepest. Hence,
0 ′is a maximum positive value. Between 0 andAthe
gradient is positive but is decreasing in value until atA
the gradient is zero, shown asA′. BetweenAandBthe
gradient is negative but is increasing in value until atB
the gradient is at its steepest. HenceB′is a maximum
negative value.
If the gradient of y=sinx is further investigated
betweenBandCandCandDthen the resulting graph
of

dy
dx

is seen to be acosine wave.
Hence the rate of change of sinxis cosx,i.e.

ify=sinxthen

dy
dx
=cosx

It may also be shown that

ify=sinax,

dy
dx

=acosax (1)

(whereaisaconstant)

andify=sin(ax+α),

dy
dx

=acos(ax+α) (2)

(whereaandαare constants).
If a similar exercise is followed fory=cosxthen the
graphs of Figure 34.6 result, showing

dy
dx

to be a graph
of sinxbut displaced byπradians.
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