Answers 241fasting, or making him eat his day's ration before starting so as to carry and
dump two rations. In the last case he would reaJIy be carrying three rations,
one inside and two on his back!
If the route had been in a straight march across a desert, the shortest time
necessary would be 86 days, as follows:
Dump 42 at 10, return to base (42 days). Dump I at 15, return to 10 (I day).
Dump 20 at 20 and return to 10 (20 days). Dump I at 20 and return to
15, pick up I and dump at 20 (I day). Dump 10 at 30 and return to 20 (10
days). Dump I at 35, return to 30 (I day). Dump 4 at 40 and return to 30
(4 days). Dump I at 40 and return to 35. Pick up I and dump at 40 (I day).
Dump 2 at 50 and return to 40 (2 days). Dump I at 55 and return to 50 (I
day). Dump I at 60 and return to 55. Pick up I and dump at 60 (I day).
March to base (2 days). Total, 86 days.
- THE BATH CHAIR
If the man leaving A goes I~ miles at 5 miles per hour, he will take 20
minutes; and the return journey at 4 miles per hour will take them 25 minutes.
He thus overtakes the invalid at 12:35, when the latter has gone ~ mile
in 35 minutes, and his rate is I Y7 miles per hour.
- THE PEDESTRIAN PASSENGER
Assume that the train runs for an hour, and that it is itself of the absurd
length of 3 miles. Then, as in the diagram, the train will have gone from B to
C = 60 miles, but the passenger will have gone from A to C, or 63 miles. On
the other hand, if he walks from the front to the rear of the train, the train will
have gone from B to C (again 60 miles), while the passenger will have gone
from B to D = 57 miles. So that in our first case the man would be travelling
over the permanent way at the rate of 63 miles per hour, and in the second
case, 57 miles per hour.60 c