Answers 257- A SQUARE OF DIGITS
In every one of the following eight sums all the nine digits are used once,
and the difference between the successive totals is, throughout, 9:
243 341 154 317 216 215 318 235
675 586 782 628 738 748 654 746
918 927 936 945 954 963 972 981- THE NINE DIGITS
The number 94,857,312, multiplied by 6, gives the product 569,143,872, the
nine digits being used once, and once only, in each case.
[Victor Meally supplies two other solutions: 89,745,321 X 6 = 538,471,926,
and 98,745,231 X 6 = 592,471,386.-M. G.)
- EXPRESSING TWENTY-FOUR
The following is a simple solution (by G. P. E.) for three 7's:From this we obtain the answer for three l's by substituting I for 7 in every
case, and putting plus instead of minus.
[Dudeney does not give solutions for the remaining digits, but Victor
Meally has supplied them:
(4+4-4)!
(5 -%)!
(~-6)!
8+8+8
(V9 + ~)!
-M.G.)