536 Puzzles and Curious Problems

(Elliott) #1
Answers 261

If the reader will work out each of these little sums in simple division he
will find that they fulfill all the conditions required by the asterisks and O's
and E's.



  1. SIMPLE DIVISION


Divide 4,971,636,104 by 124,972, and the quotient is 39,782. The reader can
now work out the little sum for himself, and he will find that all the conditions
are fulfilled. If we were allowed additional 7's in the dividend, an answer
would be 7,471,076,104 divided by 124,972 equals 59,782.



  1. A COMPLETE SKELETON


The first division sum is:

333) 100,007,892(300,324

and the second:

29)300,324( 10,356.


  1. ALPHABETICAL SUMS


The answer is as follows:

35)19775(565
175
227
210
175
175

It is clear that R cannot be I: it must therefore be either 5 or 6 to produce the
R in the second line. Then D must be 0 to give the V in the fifth line. Also M
must be 1,2, 3, or 4, if R is 5, but may be 5 if R is 6. Again, S must be an even
number if R is 5, to make D a 0, and if R is 6, then S must be 5. When we have
discovered and noted these facts, only a little trial is necessary.

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