46 Arithmetic & Algebraic Problems
- SIMPLE DIVISION
Can you restore this division
problem by substituting a figure
for every asterisk without altering
or removing the sevens? If you
start out with the assumption
that all the sevens are given and
that you must not use another,
you will attempt an impossibility,
though the proof is difficult; but
when you are told that though no
additional sevens may be used in
divisor, dividend, or quotient, any
number of extra sevens may be
used in the working, it is com-
paratively easy.
****7*)**7*******(**7**
******
*****7*
*******
*7****
*7****
*******
***7**
******
******
- A COMPLETE SKELETON
***)*********(******
* * *
* * * *
* * *
* * *
* * *
* * * *
* * * *
**)******(*****
* *
* * *
* *
* * *
* * *
* * *
* * *
It will be remembered that a
skeleton puzzle, where the figures are
represented by stars, has not been
constructed without at least one figure,
or some added condition, being used.
Perhaps the following (received from
W. J. W.) comes a little nearer the
ideal, though there are two division
sums and not one, and they are
related by the fact that the six-figure
quotient of the first happens to be the
dividend of the second. There appears
to be only one solution.
