Water Treatment 145
to the number of particles times the volume of the particles. The total volume is
thus
NVP
1 -e’
where N = number of particles and Vp = volume occupied by each particle. The total
channel volume is
NVP
e-
1 -e’
and since the total wetted surface is NAP, where Ap is the surface area of each particle,
the hydraulic radius
volume e- 1 NVP -e - ( e ) (%)
R= area - - -
wetted- perimeter area NAP 1-e
For spherical particles, VplAp = d/6, but for particles that are not true spheres,
VplAp = 4(d6), where 4 is a shape factor. For example, 4 = 0.95 for Ottawa sand,
a common filter sand. We thus have
R = (L) 1-e (4%).
Substituting Eqs. (7.4a), (7.4b), and (7.5) into Eq. (7.3b),
hL = f (b) (9) (5)
The friction factor may be approximated as
1-e
f = 150 (7) + 1.75,
(7.5)
(7.7)
where R is the Reynolds number and
The preceding discussion is applicable to a filter bed made of only one size particle.
For a bed made of nonuniform sand grains,
(7.8)