192 3 Real Analysis
Example.Find all continuous functionsf:R→Rsatisfying the equation
f(x)=λ( 1 +x^2 )
[
1 +
∫x
0
f(t)
1 +t^2
dt
]
,
for allx∈R. Hereλis a fixed real number.
Solution.Becausefis continuous, the right-hand side of the functional equation is a
differentiable function; hencefitself is differentiable. Rewrite the equation as
f(x)
1 +x^2
=λ
[
1 +
∫x
0
f(t)
1 +t^2
dt
]
,
and then differentiate with respect toxto obtain
f′(x)( 1 +x^2 )−f(x) 2 x
( 1 +x^2 )^2
=λ
f(x)
1 +x^2
.
We can separate the variables to obtain
f′(x)
f(x)
=λ+
2 x
1 +x^2
,
which, by integration, yields
lnf(x)=λx+ln( 1 +x^2 )+c.
Hencef(x)=a( 1 +x^2 )eλxfor some constanta. Substituting in the original relation,
we obtaina=λ. Therefore, the equation from the statement has the unique solution
f(x)=λ( 1 +x^2 )eλx.
A first-order differential equation can be written formally as
p(x, y)dx+q(x, y)dy= 0.
Physicists think of the expression on the left as the potential of a two-dimensional force
field, withpandqthexandycomponents of the potential. Mathematicians call this
expression a 1-form. The force field is called conservative if no energy is wasted in
moving an object along any closed path. In this case the differential equation is called
exact. As a consequence of Green’s theorem, the field is conservative precisely when the
exterior derivative
(
∂q
∂x
−
∂p
∂y
)
dxdy