P1^
6
Areas(^) below
(^) the
(^) x
axis
EXAMPLE 6.12 Find the area between the curve and the x axis for the function y = x^2 + 3 x
between x = − 1 and x = 2.
SOLUTION
The first step is to draw a sketch of the function to see whether the curve
goes below the x axis (see figure 6.17).
This shows that the y values are positive for 0 x 2 and negative for − 1 x 0.
You therefore need to calculate the area in two parts.
AreaAx xxd
xx
=+
=+
=+(
∫ ()
––
2
1032
103
3
3
2
(^01332) ))
=+
=+
=+
∫
–.
()
7
68
32
0232
023
3
3
2
6
AreaBx xxdxx(()
=
=+
=
–
.
0
26
3
7
626
3
59
6Totalarea
squareunits.y2 x–1
ABy = x^2 + 3xFigure 6.17