IntegrationP1^
6
A = B − C
= (^) ∫
3
0 (x^ +^ 1)^ dx^ −^ ∫
3
0 (x
(^2) − 2 x + 1) dx
(^) =+
+
=+()
x^2 x x xx
0(^33)
2
0
3
23
92 30 27
––
–– 33
9
2()–– 93 + 0
= squareunits.Method 2(^) A x
xx x
=
=+ +
∫{ }
()–( –)0 topcurve–bottomcurve d3((^1221 )
=
=
=
∫
∫
ddxxx xxx032
0323
033
3
23
(^2729)
(– )
–
–
=
–[]
.
0
9
2 squareunitsEXERCISE 6D 1 The diagram shows the curve
y = x^2 and the line y = 9.
The enclosed region has been shaded.
(i) Find the two points of
intersection (labelled A and B).
(ii) Using integration, show that
the area of the shaded region
is 36 square units.yO 1 3 xy = x^2 – 2x + 1y = x + 1Figure 6.20The height of this rectangle
is the height of the top
curve minus the height of
the bottom curve.yO xA By = x2y = 9