IntegrationP1^
6
! Since the integration is ‘with respect to x’, indicated by the dx and the fact that
the limits a and b are values of x, it cannot be evaluated unless the function y is
also written in terms of x.EXAMPLE 6.18 The region between the curve y = x^2 , the x axis and the lines x = 1 and x = 3 is
rotated through 360° about the x axis.
Find the volume of revolution which is formed.SOLUTION
The region is shaded in figure 6.29.Using V = (^) ∫
a
b
πy^2 dx
volume = (^) ∫
1
3
π(x^2 )^2 dx
= (^) ∫
1
3
πx^4 dx
= πx
5
1
3
5
= π 5 (– 243 1 )= 2425 π.The volume is 2425 π cubic units or 152 cubic units (3 s.f.).! Unless a decimal answer is required, it is usual to leave π in the answer, which is
then exact.O 1 3yxy = x^2Figure 6.29Since in this case
y = x^2
y^2 = (x^2 )^2 = x^4.