Cambridge International AS and A Level Mathematics Pure Mathematics 1

(Michael S) #1
Vector

(^) calculations
265
P1^
8
When you find the vector
represented by the line segment
joining two points, you are in
effect subtracting their position
vectors. If, for example,
P is the point (2, 1) and Q is the
point (3, 5), P
→
Q is 1
4






,^ as^
figure 8.16 shows.
You find this by saying
P

→
Q = P

→
O + O

→
Q = −p + q.
In this case, this gives

P

→
Q = –

2

1

3

5

1

4







+






=






as expected.
This is an important result:
P

→
Q = q − p
where p and q are the position vectors of P and Q.

Geometrical figures
It is often useful to be able to express lines in a geometrical figure in terms of
given vectors.

aCTIVITY 8.1 The diagram shows a cuboid OABCDEFG. P, Q, R, S and T are the mid-points of
the edges they lie on. The origin is at O and the axes lie along OA, OC and OD, as
shown in figure 8.17.


O

→
A =

6

0

0









,

O

→
C =

0

5

0









,

O

→
D =

0

0

4









y

2

4

6

1

3

5

(^012345) x
1
4 ))
P(2, 1)
Q(3, 5)
Figure 8.16
D E
*^6
7
)
2 A
C B
5
4
x 3
y
z
Figure 8.17

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