Chapter 6 Statistical Inference 257
where m 1 is the assumed mean of the fi rst distribution and m 2 is the mean
of the second distribution. Notice that we are not making any assumptions
about what the actual values of m 1 and m 2 are; we are interested only in the
difference between them. Because the standard deviations of the two sam-
ples are close in value, we’ll use a pooled t test to test the null hypothesis.
First, we must calculate the value of the pooled standard deviation, s:
s 5
Å
(^1) n 1212 s^2111 n 2212 s^22
n 11 n 222
5
Å
12521282112521262
2512522
5 7. 07
Thus, the t statistic equals
t 5
(^1) x 12 x 2221 m 1 2m 22
s
Å
1
n 1
1
1
n 2
5
(^175280220)
7.07
Å
1
25
1
1
25
522 .5
which should follow a t distribution with 48 degrees of freedom. Is this a
signifi cant value?
To evaluate the t statistic:
1 Open a blank workbook. In cell A1 type =TDIST(2.5,48,2) and press
Enter.
Note that we enter the value 2.5 rather than 22 .5 because the TDIST
function works with positive values. We enter the value 2 as the
third parameter because this is a two-sided test.
Excel returns a p value of 0.016, and we reject the null hypothesis. We
conclude that the evidence supports the conclusion that students learn bet-
ter how to write using the new teaching method.