27.2 CONVERGENCE OF ITERATION SCHEMES
xn xn+1xn+2
y=x
y=F(x)
ξ
x
y
Figure 27.3 Illustration of the convergence of the iteration schemexn+1=
F(xn)when0<F′(ξ)<1, whereξ=F(ξ). The liney=xmakes an angle
π/4 with the axes. The broken line makes an angle tan−^1 F′(ξ)withthex-axis.
convergence, oncexnhas become close toξ, could be very rapid indeed. If the
firstN−1 derivatives ofFvanish atx=ξ,i.e.
F′(ξ)=F′′(ξ)=···=F(N−1)(ξ) = 0 (27.18)
and consequently
n+1=O(Nn), (27.19)
then the scheme is said to haveNth-order convergence.
This is the explanation of the significant difference in convergence between the
NR scheme and the others discussed (judged by reference to (27.19), so that the
differentiability of the functionFis not a prerequisite). The NR procedure has
second-order convergence, as is shown by the following analysis. Since
F(x)=x−
f(x)
f′(x)
,
F′(x)=1−
f′(x)
f′(x)
+
f(x)f′′(x)
[f′(x)]^2
=
f(x)f′′(x)
[f′(x)]^2
.
Now, providedf′(ξ)= 0, it follows thatF′(ξ) = 0 becausef(x)=0atx=ξ.