GROUP THEORY
than they are like any element that does not belong to the set. We will find that
these divisions will be such that the group ispartitioned, i.e. the elements will be
divided into sets in such a way that each element of the group belongs to one,
and only one, such set.
We note in passing that the subgroups of a group donotform such a partition,
not least because the identity element is in every subgroup, rather than being in
precisely one. In other words, despite the nomenclature, a group is not simply the
aggregate of its proper subgroups.
28.7.1 Equivalence relations and classes
We now specify in a more mathematical manner what it means for two elements
of a group to be ‘more like’ one another than like a third element, as mentioned
in section 28.2. Our introduction will apply to any set, whether a group or not,
but our main interest will ultimately be in two particular applications to groups.
We start with the formal definition of an equivalence relation.
Anequivalence relationon a setSis a relationshipX∼Y, between two
elementsXandYbelonging toS, in which the definition of the symbol∼must
satisfy the requirements of
(i) reflexivity,X∼X;
(ii) symmetry,X∼YimpliesY∼X;
(iii) transitivity,X∼YandY∼ZimplyX∼Z.
Any particular two elements either satisfy or do not satisfy the relationship.
The general notion of an equivalence relation is very straightforward, and
the requirements on the symbol∼seem undemanding; but not all relationships
qualify. As an example within the topic of groups, if it meant ‘has the same
order as’ then clearly all the requirements would be satisfied. However, if it meant
‘commutes with’ then it would not be an equivalence relation, since althoughA
commutes withI,andIcommutes withC, this does not necessarily imply thatA
commutes withC, as is obvious from table 28.8.
It may be shown that an equivalence relation onSdivides upSintoclassesCi
such that:
(i)XandYbelong to the same class if, and only if,X∼Y;
(ii) every elementWofSbelongs to exactly one class.
This may be shown as follows. LetXbelong toS, and define the subsetSXof
Sto be the set of all elementsUofSsuch thatX∼U. Clearly by reflexivity
Xbelongs toSX. Suppose first thatX∼Y, and letZbe any element ofSY.
ThenY∼Z, and hence by transitivityX∼Z, which means thatZbelongs to
SX. Conversely, since the symmetry law givesY∼X,ifZbelongs toSXthen