PARTIAL DIFFERENTIATION
From equation (5.5) the total differential off(x, y) is given by
df=
∂f
∂x
dx+
∂f
∂y
dy,
but we now note that by using the formal device of dividing through byduthis
immediately implies
df
du
=
∂f
∂x
dx
du
+
∂f
∂y
dy
du
, (5.14)
which is called thechain rulefor partial differentiation. This expression provides
a direct method for calculating the total derivative offwith respect touand is
particularly useful when an equation is expressed in a parametric form.
Given thatx(u)=1+auandy(u)=bu^3 , find the rate of change off(x, y)=xe−ywith
respect tou.
As discussed above, this problem could be addressed by substituting forxandyto obtain
fas a function only ofuand then differentiating with respect tou. However, using (5.14)
directly we obtain
df
du
=(e−y)a+(−xe−y)3bu^2 ,
which on substituting forxandygives
df
du
=e−bu
3
(a− 3 bu^2 − 3 bau^3 ).
Equation (5.14) is an example of the chain rule for a function of two variables
each of which depends on a single variable. The chain rule may be extended to
functions of many variables, each of which is itself a function of a variableu,i.e.
f(x 1 ,x 2 ,x 3 ,...,xn), withxi=xi(u). In this case the chain rule gives
df
du
=
∑n
i=1
∂f
∂xi
dxi
du
=
∂f
∂x 1
dx 1
du
+
∂f
∂x 2
dx 2
du
+···+
∂f
∂xn
dxn
du
. (5.15)
5.6 Change of variables
It is sometimes necessary or desirable to make a change of variables during the
course of an analysis, and consequently to have to change an equation expressed
in one set of variables into an equation using another set. The same situation arises
if a functionfdepends on one set of variablesxi,sothatf=f(x 1 ,x 2 ,...,xn) but
thexiare themselves functions of a further set of variablesujand given by the
equations
xi=xi(u 1 ,u 2 ,...,um). (5.16)