Mathematical Methods for Physics and Engineering : A Comprehensive Guide

(lu) #1

VECTOR CALCULUS


total derivative, the tangent to the curver(λ) at any point is given by


dr

=

∂r
∂u

du

+

∂r
∂v

dv

. (10.21)


The two curvesu=constantandv= constant passing through any pointP

onSare calledcoordinate curves.Forthecurveu= constant, for example, we


havedu/dλ= 0, and so from (10.21) its tangent vector is in the direction∂r/∂v.


Similarly, the tangent vector to the curvev= constant is in the direction∂r/∂u.


If the surface is smooth then at any pointP onSthe vectors∂r/∂uand

∂r/∂vare linearly independent and define thetangent planeTat the pointP(see


figure 10.4). A vector normal to the surface atPis given by


n=

∂r
∂u

×

∂r
∂v

. (10.22)


In the neighbourhood ofP, an infinitesimal vector displacementdris written

dr=

∂r
∂u

du+

∂r
∂v

dv.

Theelement of areaatP, an infinitesimal parallelogram whose sides are the


coordinate curves, has magnitude


dS=





∂r
∂u

du×

∂r
∂v

dv




∣=





∂r
∂u

×

∂r
∂v




∣du dv=|n|du dv. (10.23)

Thus the total area of the surface is


A=

∫∫

R





∂r
∂u

×

∂r
∂v




∣du dv=

∫∫

R

|n|du dv, (10.24)

whereRis the region in theuv-plane corresponding to the range of parameter


values that define the surface.


Find the element of area on the surface of a sphere of radiusa, and hence calculate the
total surface area of the sphere.

We can represent a pointron the surface of the sphere in terms of the two parametersθ
andφ:


r(θ, φ)=asinθcosφi+asinθsinφj+acosθk,

whereθandφare the polar and azimuthal angles respectively. At any pointP,vectors
tangent to the coordinate curvesθ=constantandφ= constant are


∂r
∂θ

=acosθcosφi+acosθsinφj−asinθk,

∂r
∂φ

=−asinθsinφi+asinθcosφj.
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