10.7 VECTOR OPERATORS
10.7.3 Curl of a vector field
Thecurlof a vector fielda(x, y, z) is defined by
curla=∇×a=
(
∂az
∂y
−
∂ay
∂z
)
i+
(
∂ax
∂z
−
∂az
∂x
)
j+
(
∂ay
∂x
−
∂ax
∂y
)
k,
whereax,ayandazare thex-,y-andz- components ofa. The RHS can be
written in a more memorable form as a determinant:
∇×a=
∣
∣
∣
∣
∣
∣
∣
∣
ijk
∂
∂x
∂
∂y
∂
∂z
ax ay az
∣
∣
∣
∣
∣
∣
∣
∣
, (10.35)
where it is understood that, on expanding the determinant, the partial derivatives
in the second row act on the components ofain the third row. Clearly,∇×ais
itself a vector field. Any vector fieldafor which∇×a= 0 is said to beirrotational.
Find the curl of the vector fielda=x^2 y^2 z^2 i+y^2 z^2 j+x^2 z^2 k.
The curl ofais given by
∇φ=
∣∣
∣
∣∣
∣
∣∣
ijk
∂
∂x
∂
∂y
∂
∂z
x^2 y^2 z^2 y^2 z^2 x^2 z^2
∣∣
∣
∣∣
∣
∣∣
=− 2
[
y^2 zi+(xz^2 −x^2 y^2 z)j+x^2 yz^2 k
]
.
For a vector fieldv(x, y, z) describing the local velocity at any point in a fluid,
∇×vis a measure of the angular velocity of the fluid in the neighbourhood of
that point. If a small paddle wheel were placed at various points in the fluid then
it would tend to rotate in regions where∇×v= 0 , while it would not rotate in
regions where∇×v= 0.
Another insight into the physical interpretation of the curl operator is gained
by considering the vector fieldvdescribing the velocity at any point in a rigid
body rotating about some axis with angular velocityω.Ifris the position vector
of the point with respect to some origin on the axis of rotation then the velocity
of the point is given byv=ω×r. Without any loss of generality, we may take
ωto lie along thez-axis of our coordinate system, so thatω=ωk. The velocity
field is thenv=−ωyi+ωxj. The curl of this vector field is easily found to be
∇×v=
∣
∣
∣
∣
∣
∣
∣
∣
ijk
∂
∂x
∂
∂y
∂
∂z
−ωy ωx 0
∣
∣
∣
∣
∣
∣
∣
∣
=2ωk=2ω. (10.36)