LINE, SURFACE AND VOLUME INTEGRALS
R
Q
P
S
x
y
z
T
h 1 ∆u 1 eˆ 1
h 2 ∆u 2 eˆ 2
h 3 ∆u 3 eˆ 3
Figure 11.10 A general volume ∆Vin orthogonal curvilinear coordinates
u 1 ,u 2 ,u 3 .PTgives the vectorh 1 ∆u 1 ˆe 1 ,PSgivesh 2 ∆u 2 ˆe 2 andPQgives
h 3 ∆u 3 ˆe 3.
By considering the infinitesimal planar surface elementPQRSin figure 11.10, show that
(11.17) leads to the usual expression for∇×ain orthogonal curvilinear coordinates.
The planar surfacePQRSis defined by the orthogonal vectorsh 2 ∆u 2 eˆ 2 andh 3 ∆u 3 ˆe 3
at the pointP. If we traverse the loop in the directionPSRQthen, by the right-hand
convention, the unit normal to the plane isˆe 1 .Writinga=a 1 ˆe 1 +a 2 eˆ 2 +a 3 ˆe 3 , the line
integral around the loop in this direction is given by
∮
PSRQ
a·dr=a 2 h 2 ∆u 2 +
[
a 3 h 3 +
∂
∂u 2
(a 3 h 3 )∆u 2
]
∆u 3
−
[
a 2 h 2 +
∂
∂u 3
(a 2 h 2 )∆u 3
]
∆u 2 −a 3 h 3 ∆u 3
=
[
∂
∂u 2
(a 3 h 3 )−
∂
∂u 3
(a 2 h 2 )
]
∆u 2 ∆u 3.
Therefore from (11.17) the component of∇×ain the directionˆe 1 atPis given by
(∇×a) 1 = lim
∆u 2 ,∆u 3 → 0
[
1
h 2 h 3 ∆u 2 ∆u 3
∮
PSRQ
a·dr
]
=
1
h 2 h 3
[
∂
∂u 2
(h 3 a 3 )−
∂
∂u 3
(h 2 a 2 )
]
.
The other two components are found by cyclically permuting the subscripts 1, 2, 3.
Finally, we note that we can also write the∇^2 operator as a surface integral by
settinga=∇φin (11.15), to obtain
∇^2 φ=∇·∇φ= lim
V→ 0
(
1
V
∮
S
∇φ·dS
)
.