13.2 LAPLACE TRANSFORMS
A similar result may be obtained for two-dimensional Fourier transforms in
whichf(r)=f(ρ), i.e.f(r) is independent of azimuthal angleφ. In this case, using
the integral representation of the Bessel functionJ 0 (x) given at the very end of
subsection 18.5.3, we find
̃f(k)=^1
2 π
∫∞
0
2 πρf(ρ)J 0 (kρ)dρ. (13.52)
13.2 Laplace transforms
Often we are interested in functionsf(t) for which the Fourier transform does not
exist becausef→0ast→∞, and so the integral defining ̃fdoes not converge.
This would be the case for the functionf(t)=t, which does not possess a Fourier
transform. Furthermore, we might be interested in a given function only fort>0,
for example when we are given the value att= 0 in an initial-value problem.
This leads us to consider the Laplace transform,f ̄(s)orL[f(t)],off(t), which
is defined by
f ̄(s)≡
∫∞
0
f(t)e−stdt, (13.53)
provided that the integral exists. We assume here thatsis real, but complex values
would have to be considered in a more detailed study. In practice, for a given
functionf(t) there will be some real numbers 0 such that the integral in (13.53)
exists fors>s 0 but diverges fors≤s 0.
Through (13.53) we define alineartransformationLthat converts functions
of the variabletto functions of a new variables:
L[af 1 (t)+bf 2 (t)]=aL[f 1 (t)]+bL[f 2 (t)]=af ̄ 1 (s)+bf ̄ 2 (s). (13.54)
Find the Laplace transforms of the functions(i)f(t)=1,(ii)f(t)=eat,(iii)f(t)=tn,
forn=0, 1 , 2 ,....
(i) By direct application of the definition of a Laplace transform (13.53), we find
L[ 1 ]=
∫∞
0
e−stdt=
[
− 1
s
e−st
]∞
0
=
1
s
, ifs> 0 ,
where the restrictions>0 is required for the integral to exist.
(ii) Again using (13.53) directly, we find
f ̄(s)=
∫∞
0
eate−stdt=
∫∞
0
e(a−s)tdt
=
[
e(a−s)t
a−s
]∞
0
=
1
s−a
ifs>a.