13.2 LAPLACE TRANSFORMS
We may now consider the effect of multiplying the Laplace transformf ̄(s)by
e−bs(b>0). From the definition (13.53),
e−bsf ̄(s)=
∫∞
0
e−s(t+b)f(t)dt
=
∫∞
0
e−szf(z−b)dz,
on puttingt+b=z. Thuse−bsf ̄(s) is the Laplace transform of a functiong(t)
defined by
g(t)=
{
0for0<t≤b,
f(t−b)fort>b.
In other words, the functionfhas been translated to ‘later’t(larger values oft)
by an amountb.
Further properties of Laplace transforms can be proved in similar ways and
are listed below.
(i) L[f(at)]=
1
a
f ̄
(s
a
)
, (13.61)
(ii) L[tnf(t)]=(−1)n
dnf ̄(s)
dsn
, forn=1, 2 , 3 ,..., (13.62)
(iii) L
[
f(t)
t
]
=
∫∞
s
f ̄(u)du, (13.63)
provided limt→ 0 [f(t)/t] exists.
Related results may be easily proved.
Find an expression for the Laplace transform oftd^2 f/dt^2.
From the definition of the Laplace transform we have
L
[
t
d^2 f
dt^2
]
=
∫∞
0
e−stt
d^2 f
dt^2
dt
=−
d
ds
∫∞
0
e−st
d^2 f
dt^2
dt
=−
d
ds
[s^2 f ̄(s)−sf(0)−f′(0)]
=−s^2
df ̄
ds
− 2 sf ̄+f(0).
Finally we mention the convolution theorem for Laplace transforms (which is
analogous to that for Fourier transforms discussed in subsection 13.1.7). If the
functionsfandghave Laplace transformsf ̄(s)and ̄g(s)then
L
[∫t
0
f(u)g(t−u)du
]
=f ̄(s) ̄g(s), (13.64)