13.4 EXERCISES
Determine the convolution offwith itself and, without further integration,
deduce its transform. Deduce that
∫∞
−∞
sin^2 ω
ω^2
dω=π,
∫∞
−∞
sin^4 ω
ω^4
dω=
2 π
3
.
13.8 Calculate the Fraunhofer spectrum produced by a diffraction grating, uniformly
illuminated by light of wavelength 2π/k, as follows. Consider a grating with 4N
equal strips each of widthaand alternately opaque and transparent. The aperture
function is then
f(y)=
{
A for (2n+1)a≤y≤(2n+2)a, −N≤n<N,
0 otherwise.
(a) Show, for diffraction at angleθto the normal to the grating, that the required
Fourier transform can be written
̃f(q)=(2π)−^1 /^2
∑N−^1
r=−N
exp(− 2 iarq)
∫ 2 a
a
Aexp(−iqu)du,
whereq=ksinθ.
(b) Evaluate the integral and sum to show that
̃f(q)=(2π)−^1 /^2 exp(−iqa/2)Asin(2qaN)
qcos(qa/2)
,
and hence that the intensity distributionI(θ) in the spectrum is proportional
to
sin^2 (2qaN)
q^2 cos^2 (qa/2)
.
(c) For large values ofN, the numerator in the above expression has very closely
spaced maxima and minima as a function ofθand effectively takes its mean
value, 1/2, giving a low-intensity background. Much more significant peaks
inI(θ) occur whenθ= 0 or the cosine term in the denominator vanishes.
Show that the corresponding values of| ̃f(q)|are
2 aNA
(2π)^1 /^2
and
4 aNA
(2π)^1 /^2 (2m+1)π
, withmintegral.
Note that the constructive interference makes the maxima inI(θ)∝N^2 , not
N. Of course, observable maxima only occur for 0≤θ≤π/2.
13.9 By finding the complex Fourierseriesfor its LHS show that either side of the
equation
∑∞
n=−∞
δ(t+nT)=
1
T
∑∞
n=−∞
e−^2 πnit/T
can represent a periodic train of impulses. By expressing the functionf(t+nX),
in whichXis a constant, in terms of the Fouriertransform ̃f(ω)off(t), show
that
∑∞
n=−∞
f(t+nX)=
√
2 π
X
∑∞
n=−∞
̃f
(
2 nπ
X
)
e^2 πnit/X.
This result is known as thePoisson summation formula.