15.3 GENERAL ORDINARY DIFFERENTIAL EQUATIONS
but also write
d^2 y
dx^2
=
dp
dx
=
dy
dx
dp
dy
=p
dp
dy
d^3 y
dx^3
=
d
dx
(
p
dp
dy
)
=
dy
dx
d
dy
(
p
dp
dy
)
=p^2
d^2 p
dy^2
+p
(
dp
dy
) 2
, (15.78)
and so on for higher-order derivatives. This leads to an equation of one order
lower.
Solve
1+y
d^2 y
dx^2
+
(
dy
dx
) 2
=0. (15.79)
Making the substitutionsdy/dx=pandd^2 y/dx^2 =p(dp/dy) we obtain the first-order
ODE
1+yp
dp
dy
+p^2 =0,
which is separable and may be solved as in subsection 14.2.1 to obtain
(1 +p^2 )y^2 =c 1.
Usingp=dy/dxwe therefore have
p=
dy
dx
=±
√
c^21 −y^2
y^2
,
which may be integrated to give the general solution of (15.79); after squaring this reads
(x+c 2 )^2 +y^2 =c^21 .
Solution method.If the ODE does not containxexplicitly then substitutep=
dy/dx, along with the relations for higher derivatives given in (15.78), to obtain an
equation of one order lower, which may prove easier to solve.
15.3.3 Non-linear exact equations
As discussed in subsection 15.2.2, an exact ODE is one that can be obtained by
straightforward differentiation of an equation of one order lower. Moreover, the
notion of exact equations is useful for both linear and non-linear equations, since
an exact equation can be immediately integrated. It is possible, of course, that
the resulting equation may itself be exact, so that the process can be repeated.
In the non-linear case, however, there is no simple relation (such as (15.43) for
the linear case) by which an equation can be shown to be exact. Nevertheless, a
general procedure does exist and is illustrated in the following example.