Mathematical Methods for Physics and Engineering : A Comprehensive Guide

(lu) #1

APPLICATIONS OF COMPLEX VARIABLES


stationary, the magnitude of any factor,g(z), multiplying the exponential function,


exp[f(z)]∼exp[Aeiα(z−z 0 )^2 ], is at least comparable to its magnitude elsewhere,


then this result can be used to obtain an approximation to the value of the


integral ofh(z)=g(z) exp[f(z) ]. This is the basis of the method of stationary


phase.


Returning to the behaviour of a function exp[f(z) ] at one of its saddle points,

we can now see how the considerations of the previous paragraphs can be applied


there. We already know, from equation (25.62) and the discussion immediately


following it, that in the equation


h(z)≈g(z 0 ) exp(f 0 )exp{^12 Aρ^2 [cos(2θ+α)+isin(2θ+α)]}
(25.71)

the second exponent is purely imaginary on a level line, and equal to zero at


the saddle point itself. What is more, since∇ψ= 0 at the saddle, the phase is


stationary there; on one level line it is a maximum and on the other it is a


minimum. As there are two level lines through a saddle point, a path on which


the amplitude of the integrand is constant could go straight on at the saddle


point or it could turn through a right angle. For the moment we assume that it


runs continuously through the saddle.


On the level line for which the phase at the saddle point is a minimum, we can

write the phase ofh(z) as approximately


argg(z 0 )+Imf 0 +v^2 ,

wherevis real,iv^2 =^12 Aeiα(z−z 0 )^2 and, as previously,Aeiα=f′′(z 0 ). Then


eiπ/^4 dv=±


A
2

eiα/^2 dz, (25.72)

leading to an approximation to the integral of



h(z)dz≈±g(z 0 ) exp(f 0 )

∫∞

−∞

exp(iv^2 )


A
2

exp[i(^14 π−^12 α)]dv

=±g(z 0 ) exp(f 0 )


πexp(iπ/4)


A
2

exp[i(^14 π−^12 α)]



2 π
A

g(z 0 ) exp(f 0 ) exp[^12 i(π−α)]. (25.73)

Result (25.68) was used to obtain the second line above. The±ambiguity is again


resolved by the directionθof the contour; it is positive if− 3 π/ 4 <θ≤π/4;


otherwise, it is negative.


What we have ignored in obtaining result (25.73) is that we have integrated

along a level line and that therefore the integrand has the same magnitude far


from the saddle as it has at the saddle itself. This could be dismissed by referring


to the fact that contributions to the integral from the ends of the Cornu spiral

Free download pdf