The Art and Craft of Problem Solving

(Ann) #1
296 CHAPTER 8 GEOMETRY FOR AMERICANS

8.4.30 Ptolemy's Theorem is a lovely formula relat­
ing the sides and diagonals of a cyclic quadrilateral:
The sum of the products of the lengths of the oppo­
site sides is equal to the product of the lengths of the
diagonals. In other words, the diagram below satisfies
AD ·BC+DC·AB =AC ·DB.
There are many proofs of this remarkable equality.
Perhaps the shortest uses similar triangles, plus the
very clever auxiliary construction suggested below
(LDAE = LFAB). Don't be ashamed to get such a
good hint. Just finish the proof! When you are done,
prove the converse: that the equality above forces the
four points to be concyclic.

A

8.4.3 1 Let Ii and 12 be two non-intersecting circles
external to each other (i.e., one does not lie inside the
other). Let their centers, respectively. be P and Q.
Through P, draw line segments PA and PB that are
tangent to 12 (so A and B are on 12). Let C, D be the
intersection of PA and PB with Ii. Likewise, draw tan-

8.5 Transformations


Symmetry Revisited


gents QE, QF to Ii, intersecting 12 at G and H. Prove
that CD = GH.
8.4.32 (Bay Area Mathematical Olympiad 1999; orig­
inally a proposal for the 1998 IMO) Let ABCD be
a cyclic quadrilateral (a quadrilateral that can be in­
scribed in a circle). Let E and F be variable points on
the sides AB and CD, respectively, such that AE / EB =
CF /FD. Let P be the point on the segment EF such
that PE/PF =AB/CD. Prove that the ratio between
the areas of triangle AP D and BPC does not depend on
the choice of E and F.
8.4.33 (Leningrad Mathematical Olympiad 1987)
Given /::,ABC with B = 60°. Altitudes CE and AD in­
tersect at point O. Prove that the circumcenter of ABC
lies on the common bisector of angles AOE and COD.
8.4.34 (Leningrad Mathematical Olympiad 1987)
Two circles intersect at points A and B, and tangent
lines to these circles are perpendicular at each of points
A and B (in other words, the circles "meet at right an­
gles"). Let M be an arbitrary point chosen on one of
the circles so that it lies inside the other circle. Denote
the intersection points of lines AM and BM with the
latter circle by X and Y, respectively. Prove that XY is
a diameter of this circle.
8.4.35 (lMO 1990) Chords AB and CD of a circle in­
tersect at a point E inside the circle. Let M be an in­
terior point of the segment EB. The tangent line of E
to the circle through D, E, M intersects the lines BC
and AC at F and G, respectively. If AM / AB = t, find
EG/EF in terms oft.

We first discussed symmetry in Section 3.1, and by now you have seen how important
it is. Why is symmetry so ubiquitous? Many mathematical situations, when suit­
ably massaged, reveal structures that are invariant under carefully chosen "transforma­
tions." For example, the sum

1+2+3+···+ 100

is not symmetrical, but if we place the reverse sum underneath it, we create something
that is symmetric with respect to rotation about the center:

1 + 2
100 + 99

+ ... + 99
+ ... + 2

+
+

100,
1.
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