The Art and Craft of Problem Solving

(Ann) #1

  1. 5 TRANSFORMATIONS 301


S that is symmetric to A k with respect to P. (Note that Bk = Aj for some j.) By the

definition of symmetry, we have


Summing this from k = 1 to k = n implies that

By the same reasoning, we also have


� --:----t �-
QAt +QA 2 +"'+QAn = 0.

Subtracting, we get nQP = 0, so Q = P. •


Besides adding, subtracting, and multiplying vectors by scalars, we can "multiply"
two vectors with the dot-product operation. Recall the formula A .8/ (IAI· 18 1) = cos e,


where I X I denotes the magnitude of the vector X and e is the angle needed to rotate A
so that it is parallel with 8 (i.e., the "angle between" the two vectors). The dot-product
can be easily computed using coordinates, but coordinates should be avoided when
possible. Three things make dot products occasionally helpful in Euclidean geometry
problems.



  • Dot product is commutative and algebraically acts like ordinary multiplication
    in that it obeys a "distributive law:"

  • The dot product of a vector with itself equals the square of the vector's magni­
    tude: AB. AB = AB^2.

  • A.-l 8 if and only if A. 8 = O.


You may want to apply these ideas to Problems 8.5.24-8.5.26.

Reflections and Glide Reflections
A reflection across a line 1! maps each point X to a point X' such that 1! is the perpen­
dicular bisector of XX'. You are an old hand at reflections from Section 3.1. Notice
that each point in 1! is invariant with respect to reflection across 1!; this contrasts with
translations, which have no invariant points (unless the translation is the zero vector,
i.e., the identity transformation, which fixes every point).
A glide reflection along a line 1! is a composition of two maps: first a reflection
across 1!, followed by a translation parallel to 1!. Unlike reflections, a glide reflection
has no fixed points. However, the entire line 1! is fixed; in other words, every point in 1!
gets mapped to another point in 1!.

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