94 2 Work, Heat, and Energy: The First Law of Thermodynamics
PROBLEMS
Section 2.7: Calculation of Enthalpy Changes of a Class of
Chemical Reactions
2.48 Calculate∆H◦and∆U◦for the reactions at 298.15 K:
a.C 3 H 8 (g)+5O 2 (g)−→3CO 2 (g)+4H 2 O(l)
b.2SO 2 (g)+O 2 (g)−→2SO 3 (g)
c.SO 3 (g) + H 2 O(g)−→H 2 SO 4 (l)
2.49 Calculate∆H◦and∆U◦for the reactions at 298.15 K:
a.4 CuO(s)−→2Cu 2 O(s) + O 2 (g)
b.2 CO(g) + O 2 (g)−→2CO 2 (g)
c.C 2 H 5 OH(l)+3O 2 (g)−→2CO 2 (g)+3H 2 O(l)
2.50 Calculate∆H◦for the reactions of Problem 2.48 at
75 ◦C.
2.51 Calculate∆H◦for the reactions of Problem 2.49 at 75◦C.
2.52a.Find the values of the enthalpy changes of formation of
methane, carbon dioxide, and liquid water at 373.15 K,
using heat capacity values from Table A.8.
b.Using the values from part a, find the standard-state
enthalpy change for the reaction at 373.15 K:
CH 4 (g)+2O 2 (g)−→CO 2 (g)+2H 2 O(l)
c.Find the standard-state enthalpy change of the reaction
of part b, using Eq. (2.7-19). Comment on the
comparison of your answer with that of part b.
2.53 a.Calculate∆H◦for the reaction at 298.15 K:
2C 2 H 6 (g)+7O 2 (g)−→4CO 2 (g)+6H 2 O(l)
b.Using the value of∆vapHm(H 2 O) and the result of part
a, find∆H◦of this reaction for the case that the water
is vapor.
c.Recalculate this quantity using∆fHm(H 2 O(g)) and
compare with your result of part a. Comment on any
difference.
2.54 The molar enthalpy change of combustion of glycerol at
298.15 K is equal to− 393 .73 kcal mol−^1. Convert this to
kJ mol−^1 and find the value of∆fH◦of glycerol at this
temperature.
2.55 a.The molar enthalpy change of combustion of sucrose,
C 12 H 22 O 11 , at 298.15 K is equal to− 5640 .9kJmol−^1.
Calculate its enthalpy change of formation at 298.15 K.
Calculate∆U◦for the combustion reaction.
b.The molar enthalpy change of combustion of
stearic acid, C 18 H 36 O 2 , at 298.15 K is equal to
–11280.6 kJ mol−^1. Calculate its enthalpy change of
formation at 298.15 K. Compare its enthalpy change of
combustion per gram with that of sucrose.
2.56 Find the value of∆H◦for the combustion of methane
at 125◦C. State any assumptions. Assume that the
heat capacities are constant between 25◦C and
125 ◦C.
2.8 Calculation of Energy Changes of Chemical
Reactions
It would be possible to make tables of energy changes of formation and to calculate
∆Uvalues in the same way as∆Hvalues are calculated from enthalpy changes of
formation. However, adequate accuracy can be achieved without constructing a table
of∆fUvalues. From the definition of the enthalpy we can write an expression for∆U
for a chemical reaction:
∆U∆H−∆(PV) (2.8-1)
Ordinarily∆(PV) is much smaller than∆H, so that a less accurate calculation of
∆(PV) might suffice. For example, if∆His 1000 times larger than∆(PV) and if five
significant digits are desired in∆U, then five significant digits are required in∆Hbut
only two significant digits are needed in∆(PV).